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Solve the triangle. A = 54°, b = 11, c = 8 a ≈ 13.4, C ≈ 45.6, B ≈ 80.4 No triangles possible a ≈ 9, C ≈ 45.6, B ≈ 80.4 a ≈ 13.4, C ≈ 49.6, B ≈ 76.4
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need the law of cosines for this one
\[a^2=b^2+c^2-2ab\cos(A)\] \[a^2=11^2+8^2-2\times 11\times 8\cos(54)\] and a calculator
typo in the first line, should have been \[a^2=b^2+c^2-2bc\cos(A)\] second line is right though, and that is what you need
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