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Mathematics 15 Online
OpenStudy (anonymous):

The equation of the hyperbola with center at (0, 0) opening horizontally, with a = 2, b = 5 is:

Nnesha (nnesha):

\[\huge\rm \frac{ (x-h)^2 }{ a^2 }- \frac{ (y-k)^2 }{ b^2 }=1\] standard form equation of hyperbola if it's horizontal x comes first and if it's vertical then y comes first now just replace variables by their values

Nnesha (nnesha):

i'm pretty sure you should know which two points suppose to be center :-0

OpenStudy (anonymous):

Nope! Sure don't.

Nnesha (nnesha):

ohh then i will suggest u to look at ur previous post please :-0

OpenStudy (anonymous):

I got the answer, though. So thanks.

OpenStudy (anonymous):

No time for that. :-)

Nnesha (nnesha):

okay it gonna take one minute to write that down on ur notes that would be great anyways glad u got the answer :-)

OpenStudy (anonymous):

I don't take notes. Thank you for your wonderful advice though..!

Nnesha (nnesha):

\(\color{blue}{\text{Originally Posted by}}\) @xo_kansasprincess_xo Nope! Sure don't. \(\color{blue}{\text{End of Quote}}\) oopsthat's why ._.

OpenStudy (anonymous):

@Nnesha Excuse me?

Nnesha (nnesha):

huh ??

OpenStudy (anonymous):

Why is it that on every post of mine, you try to start drama with me, hmm? It's unnecessary. Unless you're going to be nicer, please do not "help" me. Thanks.

Nnesha (nnesha):

i guess you should think about that i didn't say anything and the truth is you don't need any help from me and what drama are you talking about just gimme the link thanks

OpenStudy (anonymous):

I just want you to not reply to my questions anymore. Please and thanks.

Nnesha (nnesha):

okay thanks but i really want to see that "drama post " anyways i won't .... thank u

OpenStudy (anonymous):

Mmhmm..!

Nnesha (nnesha):

mahmmm = there isn't "drama post " good luck! nd once again thanks ...

OpenStudy (anonymous):

I asked you to stop commenting. Respect that.

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