Question

A committee of four is chosen randomly from a group of six males and eight females. What is the probability that the committee includes either all males or all females? (Round your answer to four decimal places.)

Can someone help me with the answer along with the formula

Answer 1

\[\large P(all\ males)=\frac{6C4}{14C4}\]
\[\large P(all\ females)=\frac{8C4}{14C4}\]
The events 'all males' and 'all females' are mutually exclusive. Therefore the probability that the committee includes either all males or all females is given by the sum of the two values of probability.

Answer 2

@kropot72 Thank you ;)

Answer 3

You're welcome :)