Question

The work of a student to solve a set of equations is shown:

Equation 1: m = 8 + 2n
Equation 2: 3m = 4 + 4n

Step 1: −3(m) = −3(8 + 2n) [Equation 1 is multiplied by −3.]
3m = 4 + 4n [Equation 2]
Step 2: −3m = −24 − 6n [Equation 1 in Step 1 is simplified.]
3m = 4 + 4n [Equation 2]
Step 3: −3m + 3m = −24 − 6n + 4n [Equations in Step 2 are added.]
Step 4: 0 = −24 − 2n
Step 5: n = −12

In which step did the student first make an error?
A. Step 4
B. Step 3
C. Step 2
D. Step 1

Answer 1

i think its step 4 because if you figure out the problem its 0
-2*-12=24
-24+24=0

Answer 2

am i correct

Answer 3

i have no clue cx