Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

PLEASE HELP

OpenStudy (anonymous):

Sure one second please!

OpenStudy (anonymous):

TheSmartOne (thesmartone):

Is that: \(\sf\Large (2x+5x) - (24x\div 4)\)

OpenStudy (anonymous):

Right!

TheSmartOne (thesmartone):

First, what is \(2x+5x = ?\) Just think of adding 2 and 5 together and then putting the x at the end of it.

TheSmartOne (thesmartone):

Because if we had factored the x from that, we would have gotten: \(\sf (2x + 5x) = x(2+5)=?\) So what ever you get for \(\sf 2+5\) just stick the x right next to it. :)

OpenStudy (anonymous):

Sorry it = 7x

OpenStudy (anonymous):

(:

TheSmartOne (thesmartone):

correct :)

TheSmartOne (thesmartone):

so now, we need to solve the second part.

TheSmartOne (thesmartone):

What is \(\sf 24x \div 4=?\) Think of it as \(\sf\Large\frac{24x}{4}=?\)

OpenStudy (anonymous):

Okay See the girl in the picture is my sister, I'm in 9th grade so i need help i'm her other sister (:

OpenStudy (anonymous):

And also = 6x

TheSmartOne (thesmartone):

Basically, just do 24 divided by 4. And then stick the x right next to it.

TheSmartOne (thesmartone):

Correct :)

TheSmartOne (thesmartone):

So now: \(\sf\large (2x+5x) - (24x\div 4)=?\) \(\sf\large (7x) - (6x)=?\) What is \(\sf 7x-6x=?\)

TheSmartOne (thesmartone):

Hint: \(\sf x(7-6) = ?\)

OpenStudy (anonymous):

1

TheSmartOne (thesmartone):

Don't forget the x :p

OpenStudy (anonymous):

1x (:

TheSmartOne (thesmartone):

And anything times 1 is the number itself. So our final answer is \(\sf \boxed{x}\)

OpenStudy (anonymous):

Thanks so much!

TheSmartOne (thesmartone):

Anytime :)

OpenStudy (anonymous):

OpenStudy (anonymous):

Now with this one i honestly don't even know how to do?

TheSmartOne (thesmartone):

To solve that, first we need to make that into a improper fraction.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!