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Mathematics 20 Online
OpenStudy (anonymous):

Factor 6x^2+17x-3

OpenStudy (anonymous):

@mathmath333 @mathstudent55 @triciaal @welshfella

OpenStudy (anonymous):

thnx for coming

OpenStudy (xapproachesinfinity):

do ac method multiply 6 and 3 to get 18 see factor of 18 that sum up to 17

OpenStudy (xapproachesinfinity):

factor of 18 are 1,2,3,6,9,18

OpenStudy (xapproachesinfinity):

i see only 1 and 18 to sum up to 17 if it is the case -1 and 18 18-1=17

OpenStudy (anonymous):

-1 and 17?

OpenStudy (anonymous):

i mean 18 sorry

OpenStudy (xapproachesinfinity):

so we can rewrite that as \[6x^2+18x-x-3\] need to do grouping

OpenStudy (anonymous):

now what do we do?

OpenStudy (xapproachesinfinity):

yea -1 and 18 works

OpenStudy (anonymous):

oh ok

OpenStudy (xapproachesinfinity):

group the ones that have common factors

OpenStudy (xapproachesinfinity):

\[6x^2+18x-x-3=6x(x+3)-(x+3)\]

OpenStudy (xapproachesinfinity):

now x+3 is common factor again yes ?

OpenStudy (anonymous):

oh ok, yes

OpenStudy (xapproachesinfinity):

we can factor it to get the final answer

OpenStudy (xapproachesinfinity):

can you do it

OpenStudy (anonymous):

6x(x+3)-1(x+3)

OpenStudy (xapproachesinfinity):

go further

OpenStudy (xapproachesinfinity):

factor x+3

OpenStudy (anonymous):

(6x-1) (x+3)

OpenStudy (anonymous):

?

OpenStudy (xapproachesinfinity):

yes correct

OpenStudy (anonymous):

oh ok thanks can u help me with another?

OpenStudy (anonymous):

Find the solutions to x^2-5x+4=0

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