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Solve x2 - 7x = -13.
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\(\large\color{black}{ \displaystyle x^2 - 7x = -13 }\) \(\large\color{black}{ \displaystyle x^2 - 7x +(7/2)^2= -13 +(7/2)^2}\) and so forth, ... (completing the square)
A. \[x=\frac{ -7\pm i \sqrt{6} }{ 2 }\] B. \[x=\frac{ -7\pm i \sqrt{3} }{ 2 }\] C. \[x=\frac{ 7\pm i \sqrt{6} }{ 2 }\] D. \[x=\frac{ 7\pm i \sqrt{3} }{ 2 }\]
How do I do that?
@SolomonZelman
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