Question

METAL and FAN( if explained enough and is the correct answer) simplify the expression. state any excluded values4m-8/4-2m

Answer 1

is this
\[ \frac{4m-8}{4-2m} \]

Answer 2

yes

Answer 3

do you know how to factor 4 from (4m-8) ?

Answer 4

no i dont know how to factor

Answer 5

do you know about "distribute" as in
2( 3+4)= 2*3 + 2*4
?

Answer 6

14

Answer 7

yes both sides are 14. The important part is the "rule"
if you have
2(3+4) you can think of that as a "package" of (3+4)
and you have 2 packages, when you write 2(3+4)
so you must have 2 of everything inside the package: 2*3 + 2*4

Answer 8

where did you get the 2

Answer 9

It's an example.
Your life will be easier if you learn this idea.

another example, with letters
4*(m-2)
that is 4 packages of (m-2), so we should expect 4 of each thing inside the package
4(m-2) is the same as 4*m + 4*-2

Answer 10

so 2(3+4) would be my answer

Answer 11

what about the 3 also i dont understand this

Answer 12

no. But notice
4(m-2) = 4*m + 4*-2

do you see how I did that ?

Answer 13

yes i understand disturbuting but the answer to 4m-8/4-2m

Answer 14

factoring is "undoing" distributing

notice
4(m-2) = 4*m + 4*-2
we write 4*m as 4m (leave out the multiply sign)
and 4*-2 is -8
in other words
4(m-2) = 4m + -8
which can be written
4(m-2) = 4m -8

Answer 15

the idea is to rewrite 4m-8 as 4(m-2)

Answer 16

i cant understant what your doing i need you to show me in my problem i am very dilexix and cant put two problems together

Answer 17

for the bottom
(4 - 2m)
factor out -2

Answer 18

***i cant understant what your doing***
do you agree 4(m-2) = 4m-8 ?

Answer 19

yes so 4(2+m)=6+4m

Answer 20

4(2+m) is 4*2 + 4*m or 8 +4m (not 6+4m)

Answer 21

sorry i added for some reason

Answer 22

your problem has 4m-8 in the "top"
we can rewrite the top as 4(m-2)

now we look at the bottom
(4-2m)
factor out -2 (divide each term inside by -2)
(4/-2 + -2/-2 m)
and then multiply the whole thing by -2:
-2(-2 + m)
or
-2(m-2)

Answer 23

you problem becomes
\[ \frac{4m-8}{4-2m} = \frac{4(m-2)}{-2(m-2)} \]

Answer 24

if m is 2, the bottom becomes 0 (because (2-2) is zero). we do not allow divide by 0.
so write down: \( m \ne 2 \)
(don't allow m to be 2)
if m-2 is not zero, we can simplify (m-2)/(m-2) to 1
(anything divided by itself is 1)
so
\[ \frac{4m-8}{4-2m} = \frac{4(m-2)}{-2(m-2)} = \frac{4}{-2} = -2 , m \ne 2\]

Answer 25

thank you