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given sin theta= -3/5 and csc theta= -5/3 in quadrant III, find the value of cos theta and sec theta
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@perl
\[\sin(\theta)=-\frac{3}{5}\] means \[\csc(\theta)=-\frac{5}{3}\] this is one piece of information not two
you have the world famous 3 - 4 - 5 right triangle in quadrant 3 |dw:1431479269944:dw|
you can take any trig ratio you like
@satellite73 so cos= -4/5 and sec= -5/4?
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