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Evaluate the sine of angle X for the right triangle below. sinX= 7/24 24/7 7/25 24/25
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you need the hypotenuse, which you find via pythagoras do you know how to find it?
no can you help me? @satellite73
i can help you!
the hypotenuse is \(\sqrt{7^2+24^2}=25\)
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so the sine is "opposite over hypotenuse" which is \[\frac{7}{25}\]
the option closest to that, that I am given is 7/25 would that work too? @misty1212
yes that is right
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