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Mathematics 11 Online
OpenStudy (anonymous):

Inscribed angle question (with arc measures)

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

we know that angle BDC is 40 degrees we can use this to find arc BC using the inscribed angle theorem 2*(angle BDC) = arc BC 2*40 = arc BC arc BC = 80 degrees

jimthompson5910 (jim_thompson5910):

(arc AB) + (arc BC) + (arc CD) + (arc AD) = 360 120 + 80 + 110 + x = 360 solve for x to get x = ???

OpenStudy (anonymous):

so x = 1.161 approx?

OpenStudy (anonymous):

wait i"m confused so would that be the measure of measure 1?

jimthompson5910 (jim_thompson5910):

120 + 80 + 110 + x = 360 310 + x = 360 x = 360 - 310 x = 50 degrees

jimthompson5910 (jim_thompson5910):

so arc AD is 50 degrees

OpenStudy (anonymous):

omg sorry i did it wrong

OpenStudy (anonymous):

i divided instead of subtracted

jimthompson5910 (jim_thompson5910):

use the inscribed angle theorem to get angle 1 = (1/2)*(arc AD) angle 1 = (1/2)*(50) angle 1 = 25 degrees

OpenStudy (anonymous):

ohhhhh okay that makes sense now. thank you so much I appreciate it!

OpenStudy (anonymous):

if you don't mind, would you help me figure out this one?

jimthompson5910 (jim_thompson5910):

what is angle BAC? are you able to determine that value?

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