Question

Geometry help please! "Find x and y." (drawing attached)

Answer 1

@TheSmartOne

Answer 2

Use Pythagorean
\(\triangle PRQ: RQ^2 = 11^2 -y^2\)

\(\triangle RSQ: RQ^2 = x^2+9\)

\(\triangle PRS: x^2=y^2-64\)
Play with them, if your calculation is correct, you will get \(y=\sqrt{88}\) and \(x=\sqrt{24}\)

Answer 3

awesome thanks!