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OpenStudy (anonymous):
Find an equation in standard form for the hyperbola with vertices at (0, ±4) and asymptotes at y = ±2 divided by 3.x. y squared over 36 minus x squared over 16 = 1 y squared over 16 minus x squared over 36 = 1 y squared over 9 minus x squared over 4 = 1 y squared over 16 minus x squared over 9 = 1
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