Help with parabolas - QuestionCove

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OpenStudy (darkbluechocobo):

Help with parabolas

11 years ago

OpenStudy (darkbluechocobo):

A very simply supported beam is 5 feet long and has a large weight sitting at the center. The sag of the beam at its center (the difference between the bottom most point of the beam and the top of the supports) is 10 inches. Assuming that the shape of the beam is parabolic, find an equation of the parabola.

11 years ago

OpenStudy (darkbluechocobo):

I am having issues making a picture with this

11 years ago

OpenStudy (darkbluechocobo):

|dw:1431628181147:dw|

11 years ago

OpenStudy (darkbluechocobo):

@freckles

11 years ago

OpenStudy (darkbluechocobo):

|dw:1431628510710:dw|

11 years ago

OpenStudy (irishboy123):

just a suggestion

11 years ago

OpenStudy (freckles):

no no I'm sorry @IrishBoy123

11 years ago

OpenStudy (darkbluechocobo):

Man I almost had it correctly picture T_T

11 years ago

OpenStudy (freckles):

I will bathe my cats and you can play math friend to @DarkBlueChocobo

11 years ago

OpenStudy (darkbluechocobo):

|dw:1431628868543:dw|

11 years ago

OpenStudy (darkbluechocobo):

so With this we can in fact set up the equation since we have the vertex?

11 years ago

OpenStudy (darkbluechocobo):

well i guess it would be 2.5 -10 cause half of 5

11 years ago

OpenStudy (darkbluechocobo):

|dw:1431628988394:dw|

11 years ago

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