Which of the following is the equation of a circle with a radius of 4 and its center at (3, 2)?
(Points : 5)
(x + 3)^2 + (y - 2)^2 = 16

(x - 3)^2 + (y + 2)^2 = 8

(x - 3)^2 + (y + 2)^2 = 4

(x + 3)^2 + (y - 2)^2 = 4

Question

Which of the following is the equation of a circle with a radius of 4 and its center at (3, 2)?
(Points : 5)
       (x + 3)^2 + (y - 2)^2 = 16

       (x - 3)^2 + (y + 2)^2 = 8

       (x - 3)^2 + (y + 2)^2 = 4

       (x + 3)^2 + (y - 2)^2 = 4

jim_thompson5910 · Answer

General equation of a circle

(x-h)^2 + (y-k)^2 = r^2

center is (h,k)
radius is r