A private plane traveled from Seattle to the rugged wilderness at a average speed of 176 mph. on the return trip the average speed was 308 mph. if the total traveling time was 5 hours. How far is Seattle to the wilderness? please help
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OpenStudy (misty1212):
HI!!
OpenStudy (misty1212):
guess you need to use distance equals rate times time right?
OpenStudy (misty1212):
time equal distance divided by rate
OpenStudy (amber15):
yes
OpenStudy (amber15):
i'm lost on this bad
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OpenStudy (misty1212):
time going is
\[\frac{D}{175}\] and time returning is
\[\frac{D}{308}\] the total time is
\[\frac{D}{175}+\frac{D}{308}\] which you know is \(5\)
OpenStudy (amber15):
yes
OpenStudy (misty1212):
oops i made a mistake, should be 176 no matter
OpenStudy (amber15):
right
OpenStudy (misty1212):
solve
\[\frac{D}{176}+\frac{D}{308}=5\] for \(D\)
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OpenStudy (amber15):
ok
OpenStudy (misty1212):
it is not fun but i am sure you can do it
OpenStudy (amber15):
560
OpenStudy (misty1212):
let me know when you get it
OpenStudy (misty1212):
\[\color\magenta\heartsuit\]
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