Question

A private plane traveled from Seattle to a rugged wilderness at an average speed of 315mph. on the return trip the average speed was 252. if the total traveling time was 6 hours, how far is Seattle to wilderness

Answer 1

ok

Answer 2

@jim_thompson5910

Answer 3

from Seattle to the wilderness

d = r*t

d = 315*t

t = d/315

--------------------------

from the wilderness to Seattle

d = r*t

d = 252*t

t = d/252

--------------------------

Add up the two time values and set that total equal to 6. This is valid because it takes a total of 6 hours to do the round trip

(time1) + (time2) = total time

d/315 + d/252 = 6

do you know how to solve for d from here?

Answer 4

would it be 252 for d

Answer 5

d is unknown at this point

252 is the speed coming back

Answer 6

oh okay

Answer 7

d = 252 is not the solution

Answer 8

would D be 840

Answer 9

correct

Answer 10

awesome your good