Question

Please Help!!

The definite integral of the absolute value of sin2x-cos4x with the limit from 0 to pi/4

Answer 1

\[
\cos(4x)=1-2\sin^2(2x)\\
\sin(2x)-1+2\sin^2(2x)=0
2\sin^2(2x)+\sin^2(2x)-1=0\\
\]
Solve the quadratic in sin(x) and figure out where do you have to flip the graph.