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Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in standard form. 2, -4, and 1 + 3i I know the polynomial is (x-2)(x + 4)(x - (1+3i) but do I do next?
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Note that is not the whole list of zeros. This is because for a real coefficient polynomial, complex roots must come in conjugates.
ok but im not sure what to do next
do you know what the conjugate of 1 + 3i is?
no
just replace the + by -
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1 - 3i
ok so I got f(x) = x^4 - 3x^3 + 6x^2 - 18x + 80
I don't think the answer is correct. Try again and remember that \((1-3i)(1+3i)=1^2-(3i)^2=1-(-9)=10\).
( x - (1+ 3i) (x - (1-3i) = x^2 -x(1 + 3i) - x(1 - 3i0 + (1+31)(1-31) = x^2 - 2x + 10
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