Question

Help Please. I need it to be explained

Solve the equation if possible, then write the irrational numbers in simplest radical form.
x²-6x+1=0

Answer 1

Use quadratic formula...

x = [-b ± √b² - 4ac]/2a
ax² + bx + c = 0

a = 1
b = -6
c = 1

x = [6 ± √(-6)² - 4(1)(1)]/2(1)

x = [6 ± √36 - 4]/2

x = [6 ± √32]/2

x = [6 ± 4√2]/2

You get:

x = 3 ± 2√2

I hope that helps!

Answer 2

Thank you