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Will someone who is actually willing to explain how to solve this quadratic equation help me? 3x^2-12x+2=0 PLEASE NO DIRECT ANSWERS
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@freckles @paki @amistre64 @Kainui @Notamathgenius @Michele_Laino @Daniellelovee
quadratic formula
I've tried multiple times and keep getting different answers
there are a few methods, the most basic one is long, but works
\[x = (-b +or- \sqrt{b ^{2}-4ac})/2a\]
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a is 3, -12 is b, and 2 is c
we want a solution of the form (ax+n)(bx+y) expand it out and compare parts ax(bx+y) + n(bx+y) ab x^2 + ax y + bn x+n y ab x^2 + (ay+bn) x + ny ab = 3 ny = 2 ay + bn = -12
completing the square would be the next longest option i spose what method are you partial to?
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