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Find the 2 natural numbers which differ by 5 and the sum of whose square is 97 @sepeario @unklerhaukus @loser66
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\[x^2+(x+5)^2=97\]
Wait 'x + 5' I thought it would be 'x - 5'
@AaronAndyson they are same x, x+5 or x, x-5 , same
yeah doesn't really matter.
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So,what next?
solve for x, that's it
Look at the screenshot above ^
@Sepeario because you gave him the whole things, he didn't know how to solve the "almost exactly" the same problem in previous post.
No I had done like a few steps and then got.Posted it her so as to CONFIRM it @Loser66 LOL
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