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I'm stuck on 4sin theta - 3 =0 I've already added three and divided by four so Sin theta = 3/4
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is it sin^2 or just sin theta seems like sin should hve square
Nope just (4) sin [theta] -3=0 Then I added 3 to the left then divided by 4 Left with , sin theta = 3/4 Correct so far?
what they are asking ? statement ? solve for sin ?
Solve equation for theta
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