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Discrete Math 10 Online
OpenStudy (anonymous):

verify that each equation is true for every positive integer n. 1(1!) + 2(2!) + ⋯ + n(n!) = (n + 1)! – 1

OpenStudy (amistre64):

so whats our strategy?

OpenStudy (amistre64):

where should we begin our proof?

Parth (parthkohli):

\[\sum_{k=1}^{n}k\cdot k! \]\[= \sum_{k=1}^{n}(\overline{k+1} - 1) \cdot k!\]

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