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@nnesha
let DR = x CR = 3 Let area of COMPUTED = y we have 1/2 * 3 * x + y = 6 1/2 * 3* x = y
solving that system by substitution 1/2* 3x + 1/2 * 3x = 6 3x = 6 x = 2
\(A_{computer} = 6\) \(A_{CDR} = 6\) CR = 3 \(A_{CDR} = \large \frac{[CR]h}{2}=6 \)
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