Find the sine, cosine & tangent of acute angle A of triangle.
|dw:1431812447856:dw|
I think I got sin A = a/c or 7/25 = .28
given: 2 sides apply Pythagorean theorem to find 3rd side
nope sin = opposite over hyp not adjacent
\[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\]
forgot to write the BC is 7 on the picture
ohh alright |dw:1431812616422:dw| so sin A = ?
yes that pic is right now
since you know the 90 degree angle wouldn't SIN A= 7/25?
okay sin A= opposite over hyp |dw:1431812695421:dw|
yes right sin A = 7 over 25
great so I got SIN A - 7/25 and then take the sin-1 .28 = 16 degrees?
is there a box in original diagram ?
|dw:1431812909014:dw| this one
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