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Mathematics 18 Online
OpenStudy (anonymous):

l4x+1l< or =5

OpenStudy (mle):

\[|4x+1|\le 5\] this can be broken into two separate inequalities \[4x+1\le 5\]and \[4x+1 \ge -5\] solve for x for each

OpenStudy (anonymous):

|dw:1431828744125:dw|

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