Question

Factor: 24x^2y+34xy+12y
i have no idea how to do this ._.

Answer 1

what is common in all 3terms ?

Answer 2

y

Answer 3

\[\huge\rm \color{red}{y}(24x^2+34x+12) \]
now solve quadratic equation there are 3 or 4 ways to factor quadratic equation

Answer 4

So fist i would have to find a GCF right?

Answer 5

*first

Answer 6

ye right
y is common
now what is common number

Answer 7

ok so i would be left with
12x^2+17x+6 right?

Answer 8

yes right \[\huge\rm \color{red}{2y}(12x^2+17x+6) \]

Answer 9

ok so now i multiply the 12 and 6 = 72

Answer 10

am i right so far?

Answer 11

yes right :-)

Answer 12

ok and now i just solve :P
ok i know the steps from here :) thanks nn

Answer 13

ohh okay great!

Answer 14

let me know what you get :-) o^_^o

Answer 15

2y(3x+3)(4x+3)

Answer 16

hmm is there a typo ?

Answer 17

3x+3 not 4x

Answer 18

am i right? O^_^O

Answer 19

nope 4x was right

you are an expert 't foiling :D
so (3x+3)(4x+3)
foil and let's if you get 12x^2 + 17x+6

Answer 20

12x^2+8x+9x+6

Answer 21

8x*9x=72x^2

Answer 22

12x^2*6=72x^2

Answer 23

Response plz . Asker

Answer 24

numbers are right
just work on group method once again
but still pretty sure there is a typo :-)