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Linear Algebra
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2x+8 is less than or equal to x+2 is less than or equal to 3x+16 means that x is in the closed interval [a,b] where a: b:
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Are you able to solve\[2x+8 \le x+2\]
2x+8=<x+2+=<3x+16
\[2x+8 \le x+2 \le 3x+16\]
Consider it as two problems. Solving \[2x+8 \le x+2\] will give you b. Solving \[x+2 \le 3x+16\] will give you a.
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