A footpath of uniform width runs around the inside of a rectangular field 32 m long and 24 m wide.If the path occupies 208 m^2 ,find the width of the path
let footpath length be x then length = 2x+24 and width =2x+32 area = (2x+24)*(2x+32)=208 this become quadratic in x solve for x
???
@perl @amistre64
well, how would you propose we measure the area of the foot path to begin with?
Can you be more specific ?
me? no, that was as specific as i could get ..
Cam u draw figure? @Aron
@amistre64 I did not really understand your statement/post.
i asked for you thoughts about how you would attempt the solution. you must have some ideas to work with
Er has an idea, but im not sure if its correctly expressed.
Unable to understand :/ his solution
32x*2+(24-2x)x*2=208 Is it make any sence
start with drawing a picture
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