Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

Plaseee help me :(((((

OpenStudy (anonymous):

Okay, where you want to help?

OpenStudy (anonymous):

The whole question

OpenStudy (anonymous):

my bhahiyaa is always ready to help ;)

OpenStudy (anonymous):

But I choose number two to solve :(

OpenStudy (anonymous):

Or number one it doesn't matter

OpenStudy (anonymous):

What you want to do first?

OpenStudy (anonymous):

Everything , I don't even know how to start it

OpenStudy (anonymous):

I mean, which problem you want to start first?

OpenStudy (anonymous):

2

OpenStudy (anonymous):

Good..So we are starting with 2..

OpenStudy (anonymous):

You are required to choose 3 person committee, 3 persons can be male and females obviously... The main condition given is that 3 person committee will be having atleast 1 man in it.. Okay??

OpenStudy (anonymous):

Okay

OpenStudy (anonymous):

Atleast 1 man means, 3 persons can be: 1. One man and 2 Women 2. 2 men and 1 woman 3. All 3 are men.. Atleast means Greater than or equal to.. So atleast 1 man means either equal to 1 man or greater than 1 man..

OpenStudy (anonymous):

Ohhh okay

OpenStudy (anonymous):

I kinda of got it now

OpenStudy (anonymous):

Now you have got three options. just try to implement these three options.. Like one I do: For 1 man and 2 women: See, 1 man can be choosen from 4 men and 2 women can be chosen from 5 women.. So, It is : 4C1*5C2.. Like wise do for other two and then all the three..

OpenStudy (anonymous):

balle balle my bhain

OpenStudy (anonymous):

Okay thank u so much that was a lot helpful

OpenStudy (anonymous):

Can you take over from here now?

OpenStudy (anonymous):

Yesss

OpenStudy (anonymous):

Good.. If any difficulty arises, do tell here.. If not I, then someone more knowledgeable than me will definitely help you here.. :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!