Mathematics
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OpenStudy (anonymous):
A square painting has a diagonal of 44 in. Lorraine wants to frame the picture.
How many inches of frame will she need? Round to the nearest inch.
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OpenStudy (misty1212):
HI!!
OpenStudy (misty1212):
oops gone ;(
OpenStudy (anonymous):
Aww :c
OpenStudy (anonymous):
I'll just put the equation he/she needs here
OpenStudy (anonymous):
oh im here!
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OpenStudy (anonymous):
P=4A, with P being perimeter, and A being the length of one side
OpenStudy (anonymous):
soryy i closed the tabbed a sec ago.
OpenStudy (anonymous):
So 44*4=P
OpenStudy (anonymous):
oh lol
the side is the diagonal divided by the square root of two
OpenStudy (anonymous):
oh thank you very much! :3
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OpenStudy (anonymous):
it is not \(44\times 4\) for sure
OpenStudy (anonymous):
I think I just confuzzled myself, sorry I thought it just said side.
OpenStudy (anonymous):
44times 4 is 176. so it that my answer or?
OpenStudy (anonymous):
you are given the diagonal is \(44\) so the side is
\[\frac{44}{\sqrt3}\]
OpenStudy (anonymous):
44 deivded by the square root of 3?
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OpenStudy (anonymous):
*divded
OpenStudy (anonymous):
oops typo square root of two
OpenStudy (anonymous):
ah ok
OpenStudy (anonymous):
\[\frac{44}{\sqrt2}\] is one side
OpenStudy (anonymous):
all four sides are
\[\frac{4\times 44}{\sqrt2}\]
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OpenStudy (anonymous):
so i got 124.45, which rounded to the nearest tenth is 124.5. so thats my answer? :o
OpenStudy (anonymous):
i appreciate the help guys, it was correct. :D closing the question now~