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Mathematics 13 Online
OpenStudy (anonymous):

A square painting has a diagonal of 44 in. Lorraine wants to frame the picture. How many inches of frame will she need? Round to the nearest inch.

OpenStudy (misty1212):

HI!!

OpenStudy (misty1212):

oops gone ;(

OpenStudy (anonymous):

Aww :c

OpenStudy (anonymous):

I'll just put the equation he/she needs here

OpenStudy (anonymous):

oh im here!

OpenStudy (anonymous):

P=4A, with P being perimeter, and A being the length of one side

OpenStudy (anonymous):

soryy i closed the tabbed a sec ago.

OpenStudy (anonymous):

So 44*4=P

OpenStudy (anonymous):

oh lol the side is the diagonal divided by the square root of two

OpenStudy (anonymous):

oh thank you very much! :3

OpenStudy (anonymous):

it is not \(44\times 4\) for sure

OpenStudy (anonymous):

I think I just confuzzled myself, sorry I thought it just said side.

OpenStudy (anonymous):

44times 4 is 176. so it that my answer or?

OpenStudy (anonymous):

you are given the diagonal is \(44\) so the side is \[\frac{44}{\sqrt3}\]

OpenStudy (anonymous):

44 deivded by the square root of 3?

OpenStudy (anonymous):

*divded

OpenStudy (anonymous):

oops typo square root of two

OpenStudy (anonymous):

ah ok

OpenStudy (anonymous):

\[\frac{44}{\sqrt2}\] is one side

OpenStudy (anonymous):

all four sides are \[\frac{4\times 44}{\sqrt2}\]

OpenStudy (anonymous):

so i got 124.45, which rounded to the nearest tenth is 124.5. so thats my answer? :o

OpenStudy (anonymous):

i appreciate the help guys, it was correct. :D closing the question now~

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