can anyone help mehttp://ocas.pearsonschool.com/ph/cd/0-13-365946-8/?token=53616c7465645f5f81d8086b402612535c05bb36548c352efd4d42aa1f0bb0bdac910c59b0106743211d5f73e68757a01aa7c21cd8986203d225aa23afe42a72ef07f866009a4e4b

page 403 on chapter 6

Question

can anyone help mehttp://ocas.pearsonschool.com/ph/cd/0-13-365946-8/?token=53616c7465645f5f81d8086b402612535c05bb36548c352efd4d42aa1f0bb0bdac910c59b0106743211d5f73e68757a01aa7c21cd8986203d225aa23afe42a72ef07f866009a4e4b

page 403 on chapter 6

anonymous · Answer

this looks like sheer pain
which one you need to do?

bmxlifestyle · Answer

all haha i dont understand it

anonymous · Answer

which one? there are a bunch on that page

anonymous · Answer

you got your task 1
task 2
task 3

anonymous · Answer

we gotta do them all??

anonymous · Answer

help me out here...

bmxlifestyle · Answer

yea its all of them

anonymous · Answer

ok lets do the first one first

anonymous · Answer

$$3x-9y=3\
6x-3y=-24$$ solve 
any clues? no is a fine answer, just asking

anonymous · Answer

you can multiply the first equation by $-2$ all the way across and get 
$$-6x+18y=-6\
6x-9y=-24$$ then add them up

anonymous · Answer

sorry typo there should be $$-6x+18y=-6\
6x-3y=-24$$

anonymous · Answer

add and get $15y=-30$making $y=-2$

bmxlifestyle · Answer

ok did u get the rest of them @satellite73