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verify the identity. cot (x-pi/2) = -tan x
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I'm so stumped on this one. I can't figure it out at all, and I couldn't find any problems like it that might've been asked in the past.... lol
do you know the formula of cot(A-B) ?
\(\huge cot(A-B)=\bf \frac{cotAcotB+1}{cotB-cotA}\)
@zeeke u here?
Ah sorry, I was out for a bit. I assumed that's how it would begin, but I got a bit confused by what happens afterwards.
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(cot x cot pi/2 + 1)/ (cot pi/2 - cot x)?
cot pi/2 = 0 so if we plug this value into the above formula we get (0 +1) / (0 - cotx) = -1 cot x = -tan x
@welshfella oh perfect! Thank you! I gave you a medal! :)
ty yw
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