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3^-2x+1 times 3^-2x-3=3^-x
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HI!!
is it \[3^{-2x+1}\times 3^{-2x-3}=3^{-x}\]?
yes it is. im very confused.
ok we can do this, it is not that hard
when you multiply you add the exponents
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therefore the left hand side can be written as \[\huge 3^{-2x+1-2x-3}\] combine like terms, get \[\huge 3^{-4x-2}\]
since now the base on both sides is 3, the exponents must be equal as well your final job is to solve \[-4x-2=-x\] for \(x\) which is routine i imagine
you good from there?
I think so, thank you so much!(:
\[\color\magenta\heartsuit\]
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ill just tell you the answer hold on a sec
not sure if your solving for x but if you are than the answer is x=2
are you here to waste my time or to tell me if its solving for x or not
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