Question

The equation of a circle is (x+4)^2+(y−6)^2=16.
The center of the circle with the given equation is?

Answer 1

HI!!

Answer 2

hi

Answer 3

\[9(x-h)^2+(y-k)^2=r^2\\
(x-(-4))^2+(y-6)^2=4^2\]

Answer 4

ignore the 9, it is a typo!

Answer 5

lol ok

Answer 6

you can read off the center from the formula

Answer 7

you got it?

Answer 8

center is \((h,k)\) what is it in your example?

Answer 9

so (-4,6)

Answer 10

yes

Answer 11

\[\color\magenta\heartsuit\]

Answer 12

ok thank you :)

Answer 13

btw the radius is \(4\) not that you were asked

Answer 14

ty :*