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Mathematics 18 Online
OpenStudy (itsbribro):

What is the value of x? Round to the nearest tenth. http://static.k12.com/calms_media/media/1579000_1579500/1579366/1/3fa9192c258b038155292d4aed376389f3d6fe9d/MS_IMC-150126-130905.jpg

OpenStudy (rational):

use pythagoras thm : leg^2 + leg^2 = hypotenuse^2

OpenStudy (rational):

x^2 + 18^2 = 28^2

OpenStudy (itsbribro):

thank you i forgot the formula

OpenStudy (rational):

np see if you can get x isolated

OpenStudy (itsbribro):

i got 460 cause i simplified the other numbers

OpenStudy (rational):

Yes, x^2 = 460 but we're not really interested in x^2, the question is about finding just x right

OpenStudy (itsbribro):

right

OpenStudy (rational):

take "square root"

OpenStudy (itsbribro):

find the square root of 460?

OpenStudy (rational):

\[x^2 = 460\] taking square root both sides gives \[\sqrt{x^2} = \sqrt{460}\] \[x=\sqrt{460}\]

OpenStudy (rational):

Yes!

OpenStudy (itsbribro):

21?

OpenStudy (rational):

21.447... rounding to nearest tenth gives 21.4

OpenStudy (itsbribro):

ohhhh okay i knew i was forgetting a part i was like "um that dont look right" lol

OpenStudy (itsbribro):

thank you @rational

OpenStudy (rational):

yw!

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