Question

What is the equation of the circle with center (2,-5) that passes through the point (-2,10)
Can anyone help?

Answer 1

(x - 2)^2 + ( x + 5)^2 = r^2

- as the centre is at (2,-5) and r = radius

Answer 2

now as the circle passes though the point (-2,10) we can plug in x = -2 and y = 10 into the above equation
so
we can now find the values of r^2:-
(-2 -2)^2 + (-10 + 5)^2 = r^2
(-4)^2 + (-5)^2 = r^2
- calculate r^2 and you have your eqaution

Answer 3

OMG thank you!

Answer 4

yw

Answer 5

@welshfella thank for helping but im still confused the equation you explained is not one of my answer choices.