Question

4x^2+8x-11x+6-5x^2+9

A -x^2-3x+8
B -x^2+3x+3
C x^2-3x+8
D x^2+3x+3

Answer 1

D.

Answer 2

@Kitten_is_back

Answer 3

i think its A or B

Answer 4

http://www.wolframalpha.com/input/?i=4x^2%2b8x-11x%2b6-5x^2%2b9&incTime=true

Answer 5

wrong equation

Answer 6

sorry try tiger aglba

Answer 7

4x^2+8x-11x+6-5x^2+2

A -x^2-3x+8------
B -x^2+3x+3
C x^2-3x+8------
D x^2+3x+3

Answer 8

omg B and D those 3 at the end is suppose to be eight

Answer 9

http://www.tiger-algebra.com/drill/4x~2_8x-11x_6-5x~2_2/

Answer 10

4x^2+8x-11x+6-5x^2+2

A -x^2-3x+8------
B -x^2+3x+8
C x^2-3x+8------
D x^2+3x+8

Answer 11

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8,696,210 solved | 670 online

4x2+8x-11x+6-5x2+2
Final result :

-1 • (x2 + 3x - 8)

Step by step solution :
Step 1 :

Raise x to the 2nd power

Exponentiaion :

Equation at the end of step 1 :

(((((4•(x2))+8x)-11x)+6)-(5•x2))+2

Step 2 :

Raise x to the 2nd power

Exponentiaion :

Equation at the end of step 2 :

(((((4•x2)+8x)-11x)+6)-5x2)+2

Step 3 :

Simplify -x2-3x+6 + 2

Pulling out like terms :

3.1 Pull out like factors :

-x2 - 3x + 8 = -1 • (x2 + 3x - 8)
Trying to factor by splitting the middle term

3.2 Factoring x2 + 3x - 8

The first term is, x2 its coefficient is 1 .
The middle term is, +3x its coefficient is 3 .
The last term, "the constant", is -8

Step-1 : Multiply the coefficient of the first term by the constant 1 • -8 = -8

Step-2 : Find two factors of -8 whose sum equals the coefficient of the middle term, which is 3 .
-8 + 1 = -7
-4 + 2 = -2
-2 + 4 = 2
-1 + 8 = 7


Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :

-1 • (x2 + 3x - 8)

Answer 12

i think its A