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OpenStudy (anonymous):
Find the critical value of Z 0.09 rounded two decimal places
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OpenStudy (austindeboe18):
0.8212
OpenStudy (austindeboe18):
is the answer
OpenStudy (anonymous):
It said 1.48... How would I have found that??
OpenStudy (anonymous):
What about if I were trying to find the critical value of Za/2 that corresponds to the given confidence level. 91%
OpenStudy (amistre64):
use your ti83, the invnorm function
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OpenStudy (anonymous):
Can you take me through the steps please
OpenStudy (amistre64):
let me here your thoughts first ... whats your attempt
OpenStudy (anonymous):
1-0.91.09
OpenStudy (anonymous):
.09/2=.045
OpenStudy (anonymous):
Now I don't know where to go from there
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OpenStudy (amistre64):
well you did that part just great
now is where we need to use an inverse function to get from area back to z value.
OpenStudy (amistre64):
remember 2nd, VARS ??
OpenStudy (anonymous):
yes
OpenStudy (amistre64):
the invnorm function is in there ....
OpenStudy (amistre64):
invnorm(.045) gives us the z score associated with it
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OpenStudy (anonymous):
-1.69
OpenStudy (amistre64):
yes, but we tradiationally just use the positive of it.
OpenStudy (anonymous):
ugh it says its wrong
OpenStudy (anonymous):
oh ok. YES!! GOT IT! THANK YOU!!!!
OpenStudy (amistre64):
yep
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