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x^2+2x+1=0 solution set?
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-1 and -1
two roots
this (x+1)^2 so ans x=-1,-1
What about x^2+4x+4=0?
x^2 +2x + 1 =0 (x+1)^2 = 0 so x = -1 and -1
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(x+2)^2=0 x=-2,-2
x^2 + 4x +4 = 0 (x+2)^2 = 0 so x = -2 and -2
x^2-14x+49?
(x - 7) ^2 = 0 so x = 7 and 7 are the required roots
x^2+16x+64 Would be 8 right?
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(x+8)^2 = 0 so x = -8
note -8 not 8
x^2+24x+144=0 is -12?
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