Two submarines, one cruising at 25 knots and the other at 20 knots, left a naval base at the same moment. Three hours later they were 100 nautical miles apart. What was the measure of the angle between their courses?

Question

anonymous · Answer

@doodleboy98

anonymous · Answer

Okay.. so let the Naval Base be A and the positions of the ships B and C
AB = 75 knots
AC = 60
BC = 100
so with sides given you can use the cosine formula :)

anonymous · Answer

attachment

anonymous · Answer

Understand it now? :)

anonymous · Answer

So if you do your math correctly you should get 95 degrees !

anonymous · Answer

yes i do!! thank you so much :)