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Two submarines, one cruising at 25 knots and the other at 20 knots, left a naval base at the same moment. Three hours later they were 100 nautical miles apart. What was the measure of the angle between their courses?
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@doodleboy98
Okay.. so let the Naval Base be A and the positions of the ships B and C AB = 75 knots AC = 60 BC = 100 so with sides given you can use the cosine formula :)
Understand it now? :)
So if you do your math correctly you should get 95 degrees !
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yes i do!! thank you so much :)
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