Question

How do I do this trigonometric equation?

Answer 1

\[3 \csc^2 x- 2\sqrt3\cot x- 6 = 0\]

Answer 2

if 0 < x < 360

Answer 3

\[\mathbf{HINT:} ~~\cot^2\theta +1= \csc^2\theta\]

Answer 4

Then you can treat it as quadratic equation.

Answer 5

after you simplify it

Answer 6

Aiigh. I need to know my identities better. -.-

Answer 7

\[3 \cot^2 x - 2 \sqrt3 \cot x - 5 = 0\]