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OpenStudy (jojokiw3):
How do I do this trigonometric equation?
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OpenStudy (jojokiw3):
\[3 \csc^2 x- 2\sqrt3\cot x- 6 = 0\]
OpenStudy (jojokiw3):
if 0 < x < 360
geerky42 (geerky42):
\[\mathbf{HINT:} ~~\cot^2\theta +1= \csc^2\theta\]
geerky42 (geerky42):
Then you can treat it as quadratic equation.
geerky42 (geerky42):
after you simplify it
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OpenStudy (jojokiw3):
Aiigh. I need to know my identities better. -.-
OpenStudy (jojokiw3):
\[3 \cot^2 x - 2 \sqrt3 \cot x - 5 = 0\]
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