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Algebra 8 Online
OpenStudy (anonymous):

An expression is shown below: f(x) = -16x2 + 60x + 16 What are the x-intercepts of the graph of the f(x)? Show your work.

OpenStudy (anonymous):

y=−16x2+60x+16

OpenStudy (anonymous):

But what would the x intercepts be? Sorry im not good at this.. lol

OpenStudy (anonymous):

neither am i XD but hmm...lemme think a lil

OpenStudy (anonymous):

How did you come up with that then? Lol

OpenStudy (anonymous):

@xapproachesinfinity

OpenStudy (anonymous):

http://www.mathpapa.com/algebra-calculator.html thats how i came up with it XD i didnt get it and im only fourteen so i went on my favorite site to get answers for math :3

OpenStudy (anonymous):

thats the easy way out XD

OpenStudy (xapproachesinfinity):

for x intercepts solve the quadratic equation \[-16x^2+60x+16=0\]

OpenStudy (anonymous):

I'm not one who likes to just fail.. And right now I really just need an answer to this question before I'm timed out. This is my segment exam.

OpenStudy (anonymous):

How do I solve that? :/

OpenStudy (xapproachesinfinity):

quadratic formula or whatever other means you learned

OpenStudy (anonymous):

I honestly learned it a while ago and didn't expect it to be on this test.. I really just need an answer right now.

OpenStudy (xapproachesinfinity):

cannot give the answer dear, you have to work it out see open study code of conduct

OpenStudy (xapproachesinfinity):

i can lead to work out that's all

OpenStudy (anonymous):

I really don't understand it enough to work it out. A lot of people get straight out answers on here, I try to work it out and learn it myself.

OpenStudy (anonymous):

@AlexAwesome @Jaynator495 @jane11509 @Kitten_is_back

OpenStudy (anonymous):

Right now I just really can't get this question

OpenStudy (xapproachesinfinity):

\[x=\frac{-60\pm\sqrt{60^2-4(-16)(16)}}{2(-16 )}\]

OpenStudy (xapproachesinfinity):

don't tell me you forgot basic math too:)

OpenStudy (anonymous):

Can you just tell me the intercepts? There's more to the question, I just need to know that much. That's all I'm asking for.

OpenStudy (xapproachesinfinity):

can't the answer, besides, if it is a test that's more of a no answer none of the other would give you the answer. open study has a code of conduct my dear

OpenStudy (anonymous):

Yeah thanks.

OpenStudy (xapproachesinfinity):

no problem good luck

OpenStudy (anonymous):

Yup

OpenStudy (xapproachesinfinity):

wondering... part of your question says show your work, but then you are saying you just want the answer??

OpenStudy (anonymous):

Aye! I was thinking the same thing! O-O

OpenStudy (anonymous):

I'd figure it out based on the answer. But I really don't want to be going back and forth for no reason. Thanks anyways you two, have a good night.

OpenStudy (anonymous):

you too...i guess...O.o

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