Question

How does (n-1) * (sqrt{n-1} + sqrt{n-1}) = 1/ n^(3/2)

Answer 1

so is the question

\[n^{-1} \times (\sqrt{n^{-1}} + \sqrt{n^{-1}})\]

Answer 2

yes

Answer 3

For me the LHS comes to
2/(n^3/2)

Answer 4

well other than missing a negative in the power

\[n^{-1} \times 2n^{-\frac{1}{2}} = 2n^{-\frac{3}{2}}~~or~~\frac{2}{n^\frac{3}{2}}\]