Question

HELP! OR HELP GUIDE!

Answer 1

In the year 2050, humans have successfully colonized the Moon. The lunar modules created for this purpose could only house a small population of people. It is now a century later and the population has grown to 4,000 people. In the current Moon population, 10 people express the recessive phenotype for cystic fibrosis (cc genotype).

q2 –
q –
p –
p2 –
2pq –
Scenario #1 Conclusion Questions

Use this information to help you answer the following questions.
The original population’s actual genotype frequencies were:

CC – 0.73; Cc – 0.19; cc – 0.08

Answer 2

Need see the original question. Can you scan or take a snapshot?

Answer 3

In your problem q2 would be equal to the genotype frequency of the homozygous recessive cc, which is 10 out of 4,000 which is 0.0025.
If q2 is 0.0025 the q is approximately 0.16 (rounding to two decimals)

Answer 4

Sorry, that q was supposed to be 0.05

Answer 5

If q is 0.05, then p is 0.95 because they have to add up to 1.
Which makes p2 = 0.9025.

Answer 6

p2 + 2pq + q2 = 1
so 1 - p2 -q2 = 2pq and 1 - 0.9025 - 0.0025 = 0.095
OR you can multiply 2 x p x q and get the same answer.

Answer 7

you must assume the population is in genetic equilibrium to be able to figure out the allele frequencies. The only way to do that is to assume that the genotype frequency of cc is actually equal to q-squared. This is because the only number you are given is the number of people who are cc and how big the population is.

This is a bit of a problem because the population is not in equilibrium, not when you compare it to the starting population. You can tell that because q2 has changed.

So you can't really do this problem unless you assume equilibrium and it is not in equilibrium.

Is there more information to work with?

Answer 8

nope thats all it gave me
can you copy what i have and fill it in? its hard to follow

Answer 9

q2 = 0.0025
q = 0.05
p = 0.95
p2 = 0.9025
2pq = 0.095
You have to add that this is assuming Hardy Weinberg equilibrium, which the population is clearly NOT in equilibrium, but you can't do this problem unless you assume that it is.
Because the numbers don't come out the same as the original founding population, you can assume that evolution is occurring. The frequency of the recessive allele has dropped, so CF is being selected against.