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How can I factor this? 2sin2(squared)β-1=0 ?
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use difference of 2 squares
a^2 - b^2 = (a + b)(a - b)
in you case put a = sqrt2 sinβ and b = 1
cos 2x =1-2 sin ^2 x
Like this? \[2 \sin \beta - \sin \beta - 1 \]
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if you just want to solve the equation then Mohd's method is more straightforward
no factorisung would give (sqrt2 sin β + 1)(sqrt2 sinβ - 1) = 0
this will give sinβ = 1/sqrt2 or -1/sqrt2
so there are 3 solution in the range 0 to 360 degrees 1 in the first quadrant , 1 in the 3rd and 1 in the 4th.
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