Question

any nerds?

Answer 1

I only know how to solve the second one.

\[C(10,2)\frac{ 10! }{ 2!(10-2)! }\]

Answer 2

I don't think it is 10C2. I think it is 10P3.

Answer 3

Yes I meant 3. Sorry.

Answer 4

I think it is \[
10P3=\frac{10!}{(10-3)!}=10\times9\times8=720\\
10C3=\frac{10!}{3!(10-3)!}=120
\]

Answer 5

if u can explain the meaning of getting doubles i can answer ur first question

Answer 6

I guess having a double is having two dice with the same value?

Answer 7

so the first answer would be 720 and the second 120?