Question

Rewrite result in form a+bi

Answer 1

[5(sq2)]/4*(cos(5pi/4)+isin(5pi/4))

Answer 2

= [(5(sq2))/4]*(-rt2/2 - i rt2/2)

Answer 3

that is way confusing. sorry haha i'll write it in equation form xD
\[\frac{ 5\sqrt{2} }{ 4 }(\frac{ -\sqrt{2} }{ 2 }-i \frac{ \sqrt{2} }{ 2 })\]

Answer 4

so multiply in the stuff :D
just like last time!

Answer 5

\[\Large\rm \frac{5\sqrt2}{4}\cdot\frac{\sqrt2}{2}=\frac{5}{4}\cdot\frac{\sqrt2\sqrt2}{2}=\frac{5}{4}\cdot\frac{2}{2}=\frac{5}{4}\]

Answer 6

(-10/8)-(10/8)i

Answer 7

simplifyyyy :U

Answer 8

5/4

Answer 9

cool c:

Answer 10

:)