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The sum S of n successive odd number starting from 3 is given by the relation. S = n(n+2).Determine n,If the sum is 168
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@Sepeario
Ok so substitute values for S first.
S = n(n+2) 168 = n(n+2) 168 = n^2 + 2n n^2 + 2n - 168 = 0
Okay and can you factorise that now?
No :(
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give me two seconds plz.
The factorised form for this quadratic is (n-12)(n+14)
Hence the solutions: -12 and 14.
Thanks Can u help me more?
idk how much more?
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